2+2x/4x^2+1=0

Solution for 2+2x/4x^2+1=0 equation:

2+2x/4x^2+1=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

2x/4x^2+3=0

We multiply all the terms by the denominator


2x+3*4x^2=0

Wy multiply elements

12x^2+2x=0

a = 12; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·12·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*12}=\frac{-4}{24}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*12}=\frac{0}{24}
=0
$